👤
Miriama
a fost răspuns

Calculati (calcul algebric) :
a. (2x+1) * (2x-1) - (2x+1) * (2x+1) = ?
b. (x-2) * (x-3) - (x-1) * (x-5) = ?
c. (x-1) * (x-3) - (x-2) la puterea a -doua = ?
d. (x+2) * [tex] x^{2} [/tex] -x+3) - (x+1) * ( [tex] x^{2} [/tex]+2x-5) = ?

p.s: vreau rezolvari cat mai detaliate, va rog! 

Răspuns :

a. (2x+1)(2x-1-2x-1)=(2x+1)(-2)=-4x-2
b. [tex](x-2)(x-3)-(x-1)(x-5)=x^2-5x+6-x^2+6x-5=x+1[/tex]
c. [tex](x-2)^2-1-(x-2)^2=-1[/tex]
d. [tex](x+1)(x^2-x+3)+x^2-x+3-(x+1)(x^2+2x-5)=[/tex]
[tex]=(x+1)(-3x+8)+x^2-x+3=[/tex]
[tex]=-3x^2-3x+8x+8+x^2-x+3=-2x^2+4x+11[/tex]

Alte intrebari