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a fost răspuns

rezolvati exetcitiul: 19+81÷[(624÷6÷4-322÷7÷2)+3×(148-73×2)]

Răspuns :

Paraschiva13
Raspusl este: 14288.1538

Cristinabranzan13
19+81:[(624:6:4-322:7:2)+3x(148-73x2)]=
19+81:[(26-23)+3x(148-146)]=
19+81:[3+3x2]=
19+81:9=
=19+9=28

138-12×[56-3×(145÷5-19)+3×(18-3×5)]÷4=
138-12×[56-3×(29-19)+3x3]:4=
138-12×[56-3×10+3x3]:4=
138-12×[56-30+9]:4=
138-12×35:4=
138-420:4=
138-105=33