Claculez masa molara ptr.acetaldehida:M= (2X12gC+4gH+16gO)/mol=44g/mol ===> 44kg/kmol
Calculez.nr moli de acetaldehida din masa data: n sau niu=4,4kg/44kg/kmol
n= o,1kmol=100mol
1mol 1mol 1mol
CH3-CH2OH-+O----> CH3-CH0 +H20
n=100- n'=100 1oo
3mol O se obtin din1 mol dicromat
100mol n=100/3 mol dicromat
1/3mol dicromat se gasesc in 1000ml sol
100/3mol V=100000ml=100l
K2Cr2O7+4H2SO4= K2SO4+Cr2(SO4)3+4H20+3O