Răspuns :
x=9 ori 2 - 3 mai mare sau egal de cat 5.aceasta problema are mai multe solutii
[tex] \displaystyle 9(x-2)-3(2x+1)\ \textgreater \ 5x \\ 9x-18-6x-3\ \textgreater \ 5x \\ 9x-6x-5x\ \textgreater \ 18+3 \\ -2x\ \textgreater \ 21 \\ x\ \textless \ - \frac{21}{2} \\ x \in \left(- \infty , - \frac{21}{2} \right)[/tex]
