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Răspuns :

Tstefan

[tex] \frac{ 2x^{2} - 7x + 3}{ x^{2} - 9} = \frac{2 x^{2} - 6x - x + 3}{ x^{2} - 9} = [/tex]

[tex]= \frac{2x(x - 3) -(x - 3)}{(x - 3)(x + 3)} = \frac{(x - 3)(2x - 1)}{(x - 3)(x + 3)} = \frac{2x - 1}{x + 3} [/tex] 
2xpatrat-7x+3supra xpatrat-9=2xpatrat-6x-x+3supra xpatrat -9=2x(x-3)-(x-3)supra (x-3)(x+3)=(x-3)(2x-1) supra (x-3)(x+3)=2x-1supra x+3.