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Alii11
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√441+2+4+6+...+880 heeeelppppppppp

Răspuns :

Max13
[tex] \sqrt{441+2+6+...+880}= \sqrt{441+2(1+2+3+...+440)}= [/tex][tex]= \sqrt{441+2* \frac{440*441}{2} }= \sqrt{441+440*441}= \sqrt{441(440+1)} = \sqrt{ 441^{2} }=[/tex][tex]=441[/tex]

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