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a fost răspuns

calculati
a) (x+2)²
b) (3x-4)²
c) (√2+√3)²

Răspuns :

[tex]a).(x+2)^2=x^2+2 \cdot x \cdot 2+2^2=x^2+4x+4 \\ b).(3x-4)^2=(3x)^2-2 \cdot 3x \cdot 4+4^2=9x^2-24x+16 \\ c).( \sqrt{2} + \sqrt{3} )^2= \sqrt{2} ^2+2 \cdot \sqrt{2} \cdot \sqrt{3} + \sqrt{3} ^2=2+2 \sqrt{6} +3=5+2 \sqrt{6} [/tex]