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Explicație pas cu pas:

Vezi imaginea Stefanboiu
Dianageorgiana794

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[tex](3^2)^7:(3^2*3^4)^2+3^5*(3^3)^2:3^{2*5} +3^4*3^2:3^3=\\\\3^{2*7} :(3^{2+4} )^2+3^5*3^{2*3} :3^{10} +3^{4+2-3} =\\\\3^{14} :3^{6*2} +3^{5+6-10} +3^3=\\\\3^{14-12} +3^1+3^3=\\\\3^2+3^1+3^3=\\\\9+3+27=\\\\39[/tex]

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