Răspuns :
[tex]\sqrt{4} +\sqrt{3^{4} } =\sqrt{2^{2} } +\sqrt{(3^{2}) ^{2}} =2+3^{2} =2+9=11[/tex]
[tex]\bf{\sqrt{4}+\sqrt{3^4}=\sqrt{2^2}+\sqrt{(3^2})^2= 2+3^2=2+9=11 }[/tex]
[tex]\sqrt{4} +\sqrt{3^{4} } =\sqrt{2^{2} } +\sqrt{(3^{2}) ^{2}} =2+3^{2} =2+9=11[/tex]
[tex]\bf{\sqrt{4}+\sqrt{3^4}=\sqrt{2^2}+\sqrt{(3^2})^2= 2+3^2=2+9=11 }[/tex]