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AndreiutzuGamer
a fost răspuns

[tex](2^n^+^2+2^n)|(4^n^+^1+4^n)[/tex],n∈nr.natural

Răspuns :

Matepentrutoti
[tex]4^{n+1}+4^n=4^{n}(4+1)=4^n\cdot 5=2^n\cdot 2^n\cdot 5\\ 2^{n+2}+2^n=2^{n}(2^2+1)=2^n\cdot 5=\ \textgreater \ (2^{n+2}+2^n)|(4^{n+1}+4^n)[/tex]

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