Răspuns :
f:R->R, f(x)=ax+b
{ 2a+b=6
3a+b=8
{ b=6-2a
3a+6-2a=8
{ b=6-2a
a=8-6
{ b=2
a=2
{ 2a+b=6
3a+b=8
{ b=6-2a
3a+6-2a=8
{ b=6-2a
a=8-6
{ b=2
a=2
f(x)=ax+b
f(2)=6⇒2a+b=6
f(3)=8⇒3a+b=8
-----------------------------scazand relatiile:
a=2 si 4+b=8⇒b=2
f(x)=2x+2
f(2)=6⇒2a+b=6
f(3)=8⇒3a+b=8
-----------------------------scazand relatiile:
a=2 si 4+b=8⇒b=2
f(x)=2x+2