[tex] x^{2} -5x+6=0[/tex]
Trebuie sa aflam solutiile [tex] x_{1,2} [/tex] .
[tex] x^{2} -5x+6=0 \\ x^{2} -3x-2x+6=0 \\ x(x-3)-2(x-3)=0 \\
(x-3)(x-2)=0 \\ [/tex]
deci
[tex] x_{1} =2 \\ x_{2} =3[/tex]
Raportul :[tex] \frac{x_1}{x_2} + \frac{x_2}{x_1} = \frac{2}{3} + \frac{3}{2} = \frac{2*2+3*3}{6} = \frac{13}{2} =6.5[/tex]
