b)in solutia finala vom avea: 98g H₂SO₄, 196g H₃PO₄ si 882g H₂O
Msulfuric=98g/mol
Mfosforic=98g/mol
Mapa=18g/mol
n=m/M => nsulfuric=98/98=1mol; nfosforic=196/98=2moli; napa=882/18=49moli
H₂SO₄:H₃PO₄:H₂O=1:2:49
c)Masa de solutie=98+196+882=1176g
1176g solutie....................100%
98g acid sulfuric...................x% x=8,33% H₂SO₄
196g acid fosforic.................y% y=16,66% H₃PO₄
882g apa.............................z% z=75% H₂SO₄