Răspuns:
8
Explicație pas cu pas:
DE ⊥ AB, CB ⊥ AB => DE || CB
ΔAED ~ ΔABC
[tex]\frac{AE}{AB} = \frac{DE}{BC} \iff \frac{AE}{AB - AE} = \frac{DE}{BC - DE} \\\frac{AE}{BE} = \frac{DE}{BC - DE} \iff \frac{8}{x} = \frac{6}{12 - 6} \\ \frac{8}{x} = \frac{6}{6} = 1 \implies x = 8[/tex]
