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Am atasat exercitiul in fisier.​

Am Atasat Exercitiul In Fisier class=

Răspuns :

Răspuns:

Explicație pas cu pas:

Vezi imaginea Augustindevian

2^(3n+4)×5^(n-1)+3^(2n+1):31

16×2^3n×5^(n-1)+3×3^2n=

16×8^n×5^(n-1)+3×9^n=16/5×40^n+3×9^n=

16/5(31+9)^n+3×(40-31)^n=

16/5(M31+9^n)+3×(40^n-M31)=

16/5M31+(16/5)×9^n+3×(31+9)^n-M31=

16/5M31+(16/5)×9^n+3×(M31+9^n)-M31=

M31(16/5+3-1)+9^n(16/5+3)=

M31(16/5+3-1)+9^n×(16+15)/5=

M31+9^n×31/5=M31+M31=M31