[tex]\it n=2^{1996}(2^3-2^2-2-1)=2^{2\cdot998}(8-4-2-1)=(2^{998})^2\cdot1=(2^{998})^2\\ \\ m=2^{40}(2\cdot5+2\cdot3)=2^{2\cdot20}\cdot16=(2^{20})^2\cdot4^2=(4\cdot2^{20})^2[/tex]
Răspuns:
Explicație pas cu pas:
