Explicație pas cu pas:
[tex]\frac{^{3)} x + 3}{2} + \frac{^{2)}2x - 1}{3} = ^{6)}1 \\ 3(x + 3) + 2(2x - 1) = 6 \\ 3x + 9 + 4x - 2 = 6 \\ 7x + 7 = 6 \iff 7x = 6 - 7 \\ 7x = - 1 \implies x = - \frac{1}{7} [/tex]
[tex]^{4)}x + \frac{x + 3}{4} = \frac{^{2)}3x}{2} - ^{4)}2 \\ 4x + x + 3 = 6x - 8 \\ 5x - 6x = - 8 - 3 \\ - x = - 11 \implies x = 11[/tex]
