Răspuns:
n ∈ {1; 2; 3; 4; 5}
Explicație pas cu pas:
[tex]\frac{^{2)} 1}{4} < \frac{ {(n + 1)}^{2} }{8} < \frac{^{4)}11}{2} \\ 1 < {(n + 1)}^{2} < 44 \\ 36 < 44 < 49 \iff {6}^{2} < 44 < {7}^{2} \\ \implies {1}^{2} < {(n + 1)}^{2} \leqslant {6}^{2} \\ \implies 1 < n + 1 < 6 \ \ \Big|_{ - 1} \\ 0 < n \leqslant 5 \iff n \in \Big\{ 1; 2; 3; 4; 5\Big\}[/tex]
