Răspuns :
Explicație pas cu pas:
Aria pătratului:
[tex] \boxed{A_{4} = \ell_{4}^{2} \iff \ell_{4} = \sqrt{A_{4}} }[/tex]
[tex]\ell = 3 \implies A = {3}^{2} = 9[/tex]
[tex]A = 16 \implies \ell = \sqrt{16} = 4[/tex]
[tex]A = 3.25 \implies \ell = \sqrt{30.25} = 5.5[/tex]
[tex]\ell = 6.5 \implies A = {(6.5)}^{2} = 42.25[/tex]
[tex]\ell = \frac{2}{7} \implies A = {\Big( \frac{2}{7} \Big)}^{2} = \frac{4}{49} \\ [/tex]
[tex]\ell = 2 \sqrt{5} \implies A = {\Big(2 \sqrt{5} \Big)}^{2} = 20 \\ [/tex]