Răspuns :
Răspuns:
a)
[tex]19 \times 98 - 58 \times 19 = 19(98 - 58) = 19 \times 40 = 760[/tex]
b) aici sunt 2 moduri (am sa le notez cu x si y)
x:
[tex](83 - 25) \times 2 = 58 \times 2 = 116[/tex]
y:
[tex](83 - 25) \times 2 = (83 \times 2) - (25 \times 2) = 166 - 50 = 116[/tex]
c)
[tex]803 - 5 \times (256 - (12^{2} + {4}^{3} )) = 803 - 5 \times (256 - (12^{2} + 2^{6} )) = 803 - 5 \times (256 - (12^{2} + 64)) = 803 - 5 \times (256 - 12^{2} - 64) = 803 - 5 \times (192 - 12^{2} ) = 803 - 960 + 5 \times 12^{2} = 803 - 960 + 5 \times 144 = 803 - 960 + 720 = 563[/tex]
[tex]\bf c)\\ \\ \it803-5\cdot\[[256-(12^2-4^3)]=803-5\cdot\[[256-(144+64)]=\\ \\ =803-5\cdot(256-208)=803-5\cdot48=803-249=563[/tex]