Răspuns:
a) in ∆ABC, m(<A)=90 aplic tgC=AB/AC
tgC=AB/6√3
tg30=AB/6√3
√3/3=AB/6√3
3×AB=6√3×√3
3×AB=6√9
3×AB=18
AB=18:3=6
cum AM=4 cm rezulta ca MB=2 cm
