Explicație pas cu pas:
[tex]\begin{cases}5(x-3)+2y=4(y-4)-3 \\4(x-2y)=5(y-5) \end{cases} \iff \begin{cases}5x - 15 + 2y = 4y - 16 - 3 \\4x - 8y = 5y - 25 \end{cases}[/tex]
[tex]\begin{cases}5x - 2y = - 4\\4x - 13y = - 25 \end{cases}\Big|_{\cdot ( - 5)}^{\cdot 4} \iff \begin{cases}20x - 8y = - 16\\ - 20x + 65y = 125 \end{cases}[/tex]
[tex]57y = 109 \implies \bf y = \frac{109}{57} \\ [/tex]
[tex]5x - 2 \cdot \frac{109}{57} = - 4 \implies \bf x = - \frac{2}{57} \\ [/tex]
