Răspuns:
Explicație pas cu pas:
a)
[tex]\frac{^{4)}1}{3} + \frac{^{3)}3}{4} + \Big( \frac{^{2)} 2}{3} + \frac{5}{6}\Big) = \frac{4 + 9}{12} + \frac{4 + 5}{6} = \frac{13}{12} + \frac{^{2)}9}{6} = \frac{13 + 18}{12} = \bf \frac{31}{12} = 2\frac{7}{12} [/tex]
b)
[tex]\frac{7}{15} - \Big( \frac{^{3)} 3}{5} + \frac{^{5)}4}{3} + \frac{1}{15}\Big) = \frac{7}{15} - \frac{9 + 20 + 1}{15} = \frac{7 - 30}{15} = \bf - \frac{23}{15} = - 1 \frac{8}{15}[/tex]
