Arcul AB+ arcul BC=360°
Notam arc AB=x si arc BC=y
Vom avea:
x+y=360°
[tex]x=\frac{1}{5}\cdot y[/tex]
Inlocuim si obtinem:
[tex]\frac{1}{5}\cdot y+y=360\\\\ y+5y=1800\\\\6y=1800\\\\y=300\\\\x=60[/tex]
arc AB=60°
arc BC=300°
Un alt exercitiu de geometrie gasesti aici: https://brainly.ro/tema/2467391
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