Explicație pas cu pas:
b)
[tex]7 \cdot {7}^{23} : {7}^{24} = {7}^{1 + 23} : {7}^{24} = {7}^{24} : {7}^{24} = {7}^{24 - 24} = {7}^{0} = \bf 1[/tex]
c)
[tex]{11}^{50} - 11 \cdot {11}^{49} = {11}^{50} - {11}^{1 + 49} = {11}^{50} - {11}^{50} = \bf 0[/tex]
d)
[tex]{2}^{17} \cdot {2}^{18} - {2}^{34} \cdot 2 = {2}^{17 + 18} - {2}^{34 + 1} = {2}^{35} - {2}^{35} = \bf 0[/tex]
e)
[tex](29 - 2 \cdot 7)^{2} \cdot {15}^{20} - {15}^{22} = (29 - 14)^{2} \cdot {15}^{20} - {15}^{22} = (15)^{2} \cdot {15}^{20} - {15}^{22} = (15)^{2 + 20} - {15}^{22} = (15)^{22} - {15}^{22} = \bf 0[/tex]
f)
[tex](12-3)^2 \cdot (6+3)^{18} - 9^{20} = {9}^2 \cdot {9}^{18} - {9}^{20} = {9}^{2 + 18} - {9}^{20} = {9}^{20} - {9}^{20} = \bf 0[/tex]
g)
[tex](4^2:3^2)^2 \cdot 4^{18}:256^5 = {4}^{4} : {3}^{4} \cdot 4^{18} : ( {4}^{4} )^{5} = {4}^{4 + 18} : {3}^{4} : {4}^{20} = {4}^{22} : {3}^{4} : {4}^{20} = {4}^{22 - 20} : {3}^{4} = {4}^{2} : {3}^{4} = \bf \frac{16}{81}[/tex]
