Explicație pas cu pas:
8.a)
[tex]\sqrt{2} x = \sqrt{8} \iff \sqrt{2} x = 2\sqrt{2} \\ \implies \bf x = 2 [/tex]
b)
[tex]\sqrt{6}x + \sqrt{24} = 0 \iff \sqrt{6}x = - 2 \sqrt{6} \\ \implies \bf x = - 2[/tex]
c)
[tex]\sqrt{5}x - \sqrt{80} = 0 \iff \sqrt{5}x = 4 \sqrt{5} \\ \implies \bf x = 4[/tex]
d)
[tex]3\sqrt{3}x = \sqrt{75} \iff 3\sqrt{3}x = 5\sqrt{3} \\ 3x = 5\implies \bf x = \frac{5}{3} [/tex]
9.a)
[tex]\frac{4}{x} = \frac{2}{7} \iff x = \frac{4 \times 7}{2} \\ \implies \bf x = 14[/tex]
b)
[tex]\frac{7}{4} = \frac{2x}{3} \iff x = \frac{7 \times 3}{2 \times 4} \\ \implies \bf x = \frac{21}{8} [/tex]
c)
[tex]\frac{4}{9} = \frac{5}{3x} \iff x = \frac{9 \times 5}{4 \times 3} \\ \implies \bf x = \frac{15}{4} [/tex]
d)
[tex]\frac{6}{10x} = \frac{9}{15} \iff x = \frac{6 \times 15}{10 \times 9} \\ \implies \bf x = 1[/tex]
