Răspuns :
3.
[tex]\it a=\Big(\dfrac{1}{3}+\dfrac{1}{2}+\dfrac{4}{5}\Big)\cdot 30=\dfrac{30}{3}+\dfrac{30}{2}+\dfrac{120}{5}=10+15+24=49[/tex]
3.
[tex]\it a=\Big(\dfrac{1}{3}+\dfrac{1}{2}+\dfrac{4}{5}\Big)\cdot 30=\dfrac{30}{3}+\dfrac{30}{2}+\dfrac{120}{5}=10+15+24=49[/tex]