Răspuns :
6). A={√16;√12;√18;√11}
A={√11;2√3;4;3√2}
7) a/12=b/8
a/b=12/8=3/2
8) ∆dr.isoscel
ipotenuza=6√3 cm c1=c2=√(6√3)²×2=
6√3×√2=6√6cm
9)∆ABC dreptunghic <B=60°. <C=30°. BC =6cm =ipotenuza
AB cateta opusă unghiului C =30° =>
AB=BC/2
10) diagonala 1=6cm ; diagonala 2 =8cm
aria rombului=d1×d2/2=6×8/2=24cm²