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Noobplayer
a fost răspuns

mă puteți ajuta să-l aflu pe x​

Mă Puteți Ajuta Săl Aflu Pe X class=

Răspuns :

[tex]\frac{\frac{8\cdot 15+8}{15}\cdot \{[\frac{1}{5}+x(\frac{4}{3}-\frac{6}{5} )] \cdot \frac{5}{3}\} }{\frac{192}{90} }=\frac{2^{32}}{2^{30}}[/tex]

[tex]\frac{\frac{128}{15} \cdot [(\frac{1}{5}+x\cdot \frac{2}{15}) \cdot \frac{5}{3}] }{\frac{32}{15} }=\frac{2^{32}}{2^{30}}[/tex]

[tex]\frac{\frac{128}{15} \cdot \frac{3+2x}{15}\cdot \frac{5}{3} }{\frac{32}{15} }=\frac{2^{32}}{2^{30}}[/tex]

[tex]\frac{\frac{128}{135} \cdot(3+2x) }{\frac{32}{15} }=\frac{2^{32}}{2^{30}}[/tex]

[tex]\frac{128(3+2x)}{135}\cdot \frac{15}{32}=2^2\\\\ \frac{4(3+2x)}{9} =4\\\\3+2x=9\\\\2x=6\\\\x=3[/tex]

Un alt exercitiu gasesti aici: https://brainly.ro/tema/758610

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