Răspuns :
n=Cm*Vs=0,5*0,6=0,3moli
1mol.........1mol
HCOOH + NaOH -> HCOONa + H2O
a=0,3moli..0,3moli
Cm=n/Vs=0,3/0,2=1,5M
1mol.........1mol
HCOOH + NaOH -> HCOONa + H2O
a=0,3moli..0,3moli
Cm=n/Vs=0,3/0,2=1,5M
0.5=Numar moli / 0.6 LITRI => Numar moli= 0.6*0.5=0.3 moli asta inseamna
M(NaOH)=40=> 0.3
Bun. Sa pornim de la ecuatia reactiei :
22,4 40
H-COOH+NaOH->HCOO-Na+ H20
x 12
Uitasem ca Concetratia molara poate depasi 1 , Felicitari Mirceavaman