Răspuns :
[tex]\it a)\ \ 0,25=\dfrac{1}{4};\ \ \ 0,5=\dfrac{1}{2}\ .\ \ \ Exerci\c{\it t}iul\ \ devine:\\ \\ \\\Big(\dfrac{1}{4}+\dfrac{3}{4}\Big):\dfrac{1}{2}-\Big(\dfrac{1}{2}-\dfrac{1}{3}\Big):\dfrac{5}{6}=1\cdot2-\dfrac{1}{\not6}\cdot\dfrac{\not6}{5}=2-\dfrac{1}{5}=\dfrac{^{2)}9}{\ \ 5}=\dfrac{18}{10}=1,8[/tex]
[tex]\it b)\ \ -7+(-20):4=-7-5=-12\\ \\ c)\ \ 8-6\cdot(-3+9)=8-6\cdot6=8-36=-28[/tex]
[tex]\it d)\ \ \ =(-12+6):(-6)+4=1+4=5[/tex]
[tex]\it e)\ \ \ =(-10)\cdot(-3+4)=-10\cdot1=-10[/tex]