Răspuns :
s - sticle
b - bidoane
16s+4b=24l
4s+6b=16l/·(-4)⇔16s+4b=24l
-16s-24b=-64l⇔/-20b=-40/·(-1)⇒20b=40⇒b=40/20=2l⇒un bidon conţine 2l de ulei
16s+4·2=24l⇒16s+8=24⇒16s=24-8=16⇒s=16/16=1l⇒o sticlă conţine 1l de ulei
b - bidoane
16s+4b=24l
4s+6b=16l/·(-4)⇔16s+4b=24l
-16s-24b=-64l⇔/-20b=-40/·(-1)⇒20b=40⇒b=40/20=2l⇒un bidon conţine 2l de ulei
16s+4·2=24l⇒16s+8=24⇒16s=24-8=16⇒s=16/16=1l⇒o sticlă conţine 1l de ulei