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Vali68
a fost răspuns

Cate grame de dicromat de potasiu se gasesc in 200mL solutie de concentratie 0,2N?

Răspuns :

C=n/vs
n=CxVs
n=0,2x02=0,04
n=m/masa moleculara 
m=nx masa moleculara 
m=294x0,04=11,76 g
Mirceavaman
Cm=n/Vs => n=Cm*Vs=0,2*0,2=0,04moli K2Cr2O7
n=m/M
Mdicromat=39*2+52*2+16*7=78+104+112=294g/mol
m=0,04*294=11,76g K2Cr2O7