Răspuns:
n ∈ {3, 4, 5}
Explicație pas cu pas:
[tex]\frac{3}{8} < \frac{n - 1}{3} < \frac{3}{2} \ \Big|_{(×3)} \\ [/tex]
[tex]\frac{9}{8} < n - 1 < \frac{9}{2} \ \Big|_{( + 1)} \\ [/tex]
[tex]\frac{9}{8} + 1 < n < \frac{9}{2} + 1\\ [/tex]
[tex]1\frac{1}{8} + 1 < n < 4\frac{1}{2} + 1\\[/tex]
[tex] \implies 3 \leqslant n \leqslant 5[/tex]
n ∈ {3, 4, 5}
