Răspuns:
4 intregi 23/49 = (4x49+23)/49 = 219/49
1 intreg 1/49 = (1x49+1)/49 = 50/49
2 intregi 30/49 = (2x49+30)/49 = 128/49
3 intregi 15/49 = (3x49+15)/49 = 162/49
= √(219/49) + √(50/49) + √(128/49) - √(162/49) =
= √219/√49 + √50/√49 + √128/√49 - √162/√49 =
= √219 / 7 + 5√2/7 + 8√2/7 - 9√2/7 =
= (√219 + 5√2 + 8√2 - 9√2) / 7 =
= (√219 + 4√2) / 7
Posibil ai scris gresit primul radical
