[tex]volumul\;piramidei\;V=\frac{A_b\cdot{h}}{3}\Rightarrow\;V=\frac{48^2\cdot{h}}{3}\;\;;\\
A_l=\frac{P_b*a_p}{2}\;\;adica:\;3840cm^2=\frac{4*48*a_p}{2}\\
\rughtarrow\;a_p=3840:(2*48)=40cm\;;\\Din\;\Delta\;dreptunghic\;format\;de\;inaltime\;;\;apotema\;si \\
jumatatea\;laturii\;bazei,\;h=\sqrt{40^2-24^2}=\sqrt{2176}\approx46,6cm\\
\Rightarrow\,V=(48^2*46,6):3=35788,8cm^3=35,7888dm^3\approx35,8 \;litrii[/tex]
