Răspuns:
d) 3√3
Explicație pas cu pas:
[tex]2 \sqrt{7} = \sqrt{ {2}^{2} \times 7} = \sqrt{4 \times 7} = \sqrt{28} [/tex]
[tex]3 \sqrt{3} = \sqrt{{3}^{2} \times 3} = \sqrt{ {3}^{3} } = \sqrt{27} [/tex]
[tex]4 \sqrt{2} = \sqrt{ {4}^{2} \times 2 } = \sqrt{16 \times 2} = \sqrt{32} [/tex]
[tex] \sqrt{27} < \sqrt{28} < \sqrt{30} < \sqrt{32} \\ 3 \sqrt{3} < 2 \sqrt{7} < \sqrt{30} < 4 \sqrt{2} [/tex]
