Explicație pas cu pas:
b)
[tex]{3}^{20} \times {2}^{20} - {6}^{23} \div {6}^{3} = {(3 \times 2)}^{20} - {6}^{23 - 3} = \\ = {6}^{20} - {6}^{20} = 0[/tex]
c)
[tex]{2}^{18} \times {12}^{18} \div ( {6}^{16} \times {4}^{16}) = {(2 \times 12)}^{18} \div {(6 \times 4)}^{16} = \\ = {24}^{18} \div {24}^{16} = {24}^{18 - 16} = {24}^{2} = 576[/tex]
d)
[tex]{75}^{38} \div {25}^{38} - {( {3}^{19} )}^{2} = {(75 \div 25)}^{38} - {3}^{19 \times 2} = \\ = {3}^{38} - {3}^{38} = 0[/tex]
e)
[tex]{26}^{27} \div {13}^{27} \div {2}^{ {5}^{2} } = {(26 \div 13)}^{27} \div {2}^{25} = \\ = {2}^{27} \div {2}^{25} = {2}^{27 - 25} = {2}^{2} = 4[/tex]
f)
[tex]{10}^{64} \div {2}^{64} - {5}^{ {4}^{3} } = {(10 \div 2)}^{64} - {5}^{64} = \\ = {5}^{64} - {5}^{64} = 0[/tex]
