Răspuns:
Andreea: 14
Explicație pas cu pas:
[tex]|4 \sqrt{3} - 8| = 8 - 4 \sqrt{3}[/tex]
[tex]a = |4 \sqrt{3} - 8| - \frac{6}{3 - 2 \sqrt{3} } = 8 - 4 \sqrt{3} - \frac{6(3 + 2 \sqrt{3})}{(3 - 2 \sqrt{3})(3 + 2 \sqrt{3})} \\ = 8 - 4 \sqrt{3} - \frac{6(3 + 2 \sqrt{3})}{ {3}^{2} - {(2 \sqrt{3})}^{2} } = 8 - 4 \sqrt{3} - \frac{6(3 + 2 \sqrt{3})}{9 - 12} \\ = 8 - 4 \sqrt{3} - \frac{6(3 + 2 \sqrt{3})}{- 3} = 8 - 4 \sqrt{3} + 2(3 + 2 \sqrt{3}) \\ = 8 - 4 \sqrt{3} + 6 + 4 \sqrt{3} = 14[/tex]
