Explicație pas cu pas:
d)
[tex] {2}^{17} \times {2}^{18} - {2}^{34} \times {2}^{} = {2}^{17 + 18} - {2}^{34 + 1} \\ = {2}^{35} - {2}^{35} = {2}^{35}\cdot (1 - 1) = {2}^{35}\cdot 0 = 0[/tex]
e)
[tex]{(29 - 2 \times 7)}^{2} \times {15}^{20} - {15}^{22} = {(29 - 14)}^{2} \times {15}^{20} - {15}^{22} \\ = {(29 - 2 \times 7)}^{2} \times {15}^{20} - {15}^{22} = {15}^{2} \times {15}^{20} - {15}^{22} \\ = {15}^{2 + 20} - {15}^{22} = {15}^{22} - {15}^{22} = 0[/tex]
f)
[tex]{(12 - 3)}^{2} \times {(6 + 3)}^{18} - {9}^{20} = {9}^{2} \times {9}^{18} - {9}^{20} \\ = {9}^{2 + 18} - {9}^{20} = {9}^{20} - {9}^{20} = 0[/tex]
g)
[tex]{( {4}^{2} \div {2}^{2})}^{2} \times {4}^{18} \div {256}^{5} = {(16 \div 4)}^{2} \times {4}^{18} \div {( {4}^{4} )}^{5} \\ = {4}^{2} \times {4}^{18} \div {4}^{20} = {4}^{2+18} \div {4}^{20} = {4}^{20} \div {4}^{20} \\ = {4}^{20-20} = {4}^{0} = 1[/tex]
