Salut!
Ai rezolvarea in C++ mai jos
#include <iostream>
#include <cmath>
#include <iomanip>
using namespace std;
int main()
{
/*
* Teorema medianei:
* MA = mediana trasa din punctul A pe latura BC
* MA*MA = ( 2*(AB*AB+AC*AC) - BC*BC ) / 4
*
* Un triunghi exista daca:
* AB+AC >= BC si AB+BC >= AC si BC+AC >= AB
*/
double a, b, c, MA, MB, MC;
// a = AB, b = BC, c = AC
cin >> a >> b >> c;
if (a + b >= c && a + c >= b && b + c >= a)
{
MA = sqrt((2 * (b * b + c * c) - a * a) / 4);
MB = sqrt((2 * (a * a + c * c) - b * b) / 4);
MC = sqrt((2 * (b * b + a * a) - c * c) / 4);
//Fixes
MA = (int)(MA * 100) / 100.0;
MB = (int)(MB * 100) / 100.0;
MC = (int)(MC * 100) / 100.0;
cout << fixed << setprecision(2) << MA << " " << MB << " " << MC;
}
else
{
cout << "Imposibil";
}
return 0;
}
- Ti-am atasat si fisierul mai jos
