Răspuns :
Explicație pas cu pas:
[tex] log_{2}(4) + log_{3}(27) = log_{2}( {2}^{2} ) + log_{3}( {3}^{3} ) \\ = 2 log_{2}(2) + 3log_{3}(3) = 2 + 3 = 5[/tex]
[tex]\it log_24+log_327=log_22^2+log_33^3=2log_22+3log_33=2\cdot1+3\cdot1=5[/tex]
Explicație pas cu pas:
[tex] log_{2}(4) + log_{3}(27) = log_{2}( {2}^{2} ) + log_{3}( {3}^{3} ) \\ = 2 log_{2}(2) + 3log_{3}(3) = 2 + 3 = 5[/tex]
[tex]\it log_24+log_327=log_22^2+log_33^3=2log_22+3log_33=2\cdot1+3\cdot1=5[/tex]