Răspuns:
NH4Cl
MNH4Cl=14+1x4+35,5=53,5g/mol
r.a. N:H:Cl=1:4:1
r.m. N:H:Cl=14:4:35,5
compozitie procentuala
53,5gNH4Cl..............14gN...............4gH.............35,5gCl
100gNH4Cl................x%N................y%H....................z%Cl
x=100x14/53,5=calculeaza
y=100x4/53,5=calculeaza
z=100x35,5/53,5=calculeaza
Explicație: