Notam distanta cu d.
Avem:
[tex]d=\frac{20}{100} d+40+\frac{30}{100}(d-\frac{20}{100}d-40)+72+124[/tex]
[tex]d=\frac{20}{100}d+40+\frac{30}{100}d-\frac{6}{100}d-\frac{120}{100}+196[/tex]
[tex]d=\frac{44}{100}d+236-\frac{120}{100}[/tex]
[tex]d-\frac{44}{100}d=\frac{23.600-120}{100}[/tex]
[tex]\frac{56}{100}d=\frac{23.480}{100}[/tex]
[tex]d=\frac{23.480}{56}[/tex]
[tex]d=419,29 km[/tex]
In cea de-a doua zi biciclistul a parcurs
[tex]\frac{24}{100}d-\frac{120}{100}+72=\frac{10.062,96}{100}-\frac{120}{100}+\frac{7.200}{100}=171,43km[/tex]
Raportam la intreaga distanta si obtinem
[tex]\frac{171,43}{419,29}= 0,4089[/tex]
Inmultim cu 100 si obtinem procentul de 40,89%, atat a parcurs biciclistul in ziua a doua raportat la distanta parcursa in toate cele 3 zile.
