Răspuns:
6 K N O3 + 10 Fe → 5 Fe 2 O 3 + 3 K 2 O + 3 N 2
6 N V + 30 e - → 6 N 0 (reducere) agent oxidant
10 Fe 0 - 30 e - → 10 Fe III (oxidare) agent reducator
