[tex]\displaystyle\bf\\(x+2)^2+(3-y)^2=0\\\\(x+2)^2=0~~si~~(3-y)^2=0\\\\x+2=0\implies~\boxed{\bf x=-2}\\\\3-y=0\implies~\boxed{\bf y=3}\\\\x+y=-2+3\\\\\boxed{\bf x+y=1}\\\\Raspuns~corect~d)[/tex]
