Răspuns:
Explicație pas cu pas:
a) lim x->inf(x -lnx) = lim x->inf(ln(e^x) -lnx) =
lim x->inf(ln(e^x/x) ) = inf
b) lim x->0(x -lnx) =
lim x->inf(ln(e^x/x) ) =
lim x->inf(ln(e^0/0) ) = 1/0 = inf
x = 0 asimpt. verticala
Nu are asimpt. orizontala ( lim x->inf f(x) = inf)
y = mx +n ec. asimpt. oblice
m = lim x->inf(f(x)/x) = lim x->inf(1 -lnx/x) = 1
n = lim x->inf(f(x) -mx) =
lim x->inf(x -lnx -x) =
lim x->inf( -lnx) = -inf
Nu are asimpt. oblica
