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a fost răspuns

A) 1000ml solutie NaOH 1M
b) 500ml solutie CuSO4 0. 5M
c) 2400ml solutie KNO3 0. 02M
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md= ?

repede va rog am test.

Răspuns :

Mihaiimbrisca

Răspuns:

a)

Vs=1000ml=1L

CM=ν/Vs

ν=CMxVs=1x1=1mol NaOH

MNaOH=23+16+1=40g/mol

m=νxM=1x40=40g

b)

Vs=500ml=0,5L

CM=ν/Vs

ν=CMxVs=0,5x0,5=0,25mol CuSO4

MCuSO4=64+32+4x16=160g/mol

m=νxM=0,25x160=40g

c)

Vs=2400ml=2,4 L

ν=CMxVs= 0,02X2,4 mol=0,048molKNO3

MKNO3=39+14+3x16=101g/mol

m= νxM= 0,048X101g=4,848g

Explicație:

ν- niu