Salut!
Ai mai jos rezolvarea in C++
#include <iostream>
using namespace std;
int main()
{
int n, m, a[101][101], s = 0, cnt = 0;
cin >> n >> m;
for (int i = 1; i <= n; ++i)
{
for (int j = 1; j <= m; ++j)
{
cin >> a[i][j];
}
}
for (int i = 1; i <= n; ++i)
{
if (i % 2 != 0)
{
for (int j = 1; j <= m; ++j)
{
s += a[i][j];
cnt++;
}
}
}
cout << (double)s/cnt;
return 0;
}
