Răspuns:
1mol.........................1mol
C2H5OH + O2 → CH3-COOH + H2O
8moli..........................xmoli
x=8moli CH3-COOH
η=100% ...............8moliCH3-COOH
η=75%...................ymoli
y=75x8/100=6moli CH3-COOH
MCH3-COOH=2x12+4x1+2x16=60g/mol
m=nxM=6x60=360gCH3-COOH
Explicație: